Roulette System | How to Win at Roulette | Online Roulette Strategy

NEWS: Kim J. from North Carolina has just won $1,708.91 with the Andruchi System.

Congratulations Kim!

Let me work through a simplified example to keep things uncomplicated to start off with. If you find the explanation below a bit dense and difficult to understand, do not worry because you do not need to fully understand it in order to use my System successfully just like you do not need to know how a Car engine works in order to drive it. Feel free to skim thorough this section if that is the case and keep in mind that the only thing you need to do to use my System successfully is press a few buttons based on the spins that have been generated as all the math is calculated "under the hood".

My program is based on the probability distribution of unique numbers in consecutive spins. Just to be clear, a unique number is simply a number that has been spun, counted only once regardless of how many times it has repeated in that particular sequence. So for example, if the numbers 0, 36, and 0 were spun on the roulette wheel, that would be 2 unique numbers (0 and 36) in 3 consecutive spins.

Now let's consider a 10 consecutive spin example. I ran 10,000 simulations and calculated the probability of how many unique numbers show up in 10 consecutive spins. In other words, I calculated the probability distribution of how many different numbers actually come out in 10 spins. This is shown below:

Probability Distribution of Unique Numbers in 10 Consecutive Spins.
Based on 10,000 simulations.

So for example, in the 10,000 simulations I ran, exactly 8 unique numbers (and 2 repeaters) appeared in 10 consecutive spins approximately 24% of the time (roughly 2,400 times out of 10,000 simulations). If you know the probabilities above, then you know that the probability of 8, 9, or 10 unique numbers coming out in 10 consecutive spins is simply the sum of their probabilities (confer above): 24% + 42% + 27% = 93%. In other words, 8, 9, or 10 unique numbers (e.g. 8 or greater) will appear in any consecutive 10-spin sequence 93% of the time (that's more than 9 out of 10 times, try it yourself in the interactive example above). So if in 7 consecutive spins, 7 unique numbers have appeared (e.g. no repeaters by the 7th spin), then the probability of at least one more unique numbers appearing in the next 3 spins (to complete the 10-spin sequence) is simply the probability of 8, 9, or 10 unique numbers appearing, which we already know to be 93%. In other words, if 7 different numbers come out in 7 consecutive spins, there is a 93% chance that at least one of the numbers that have not come up (e.g. a new unique numbers) will show up in the next 3 spins (until the end of the 10-spin sequence). So at that point, we could bet on all those 30 numbers that have not come out for the next 3 spins and we would have a 93% probability of winning. That is, in essence, the basis of the Andruchi System (it's actually a bit more complicated as I will explain below).

But what if in a 10 consecutive spin sequence, 6 numbers come out in 7 spins (e.g. one of the numbers repeated itself)? Would you take into account the 27% probability of a total of 10 unique numbers showing up in the next 3 spins when calculating the probability of success? Of course not because if only 6 unique numbers come out in 7 spins, then the maximum number of unique numbers that could possibly come out in 10 spins is: 6 unique numbers + 3 spins left = 9 unique numbers. So in this particular example, you would not account for the 27% probability of 10 unique numbers occurring in a 10 consecutive spin sequence since it cannot happen. So what do you do? Well, let's look at all the possible outcomes: there are only 3 spins left and there are 6 unique numbers that have been spun, so there are only 4 possible outcomes: 1) the next 3 spins repeat the last 7 numbers and we still end up with a total of 6 unique numbers, 2) the next 3 spins produce only 1 more unique number (and 2 repeaters), so we end up with 7 unique numbers, 3) the next 3 spins produce 2 more unique numbers (and only 1 repeater), so we end up with 8 unique numbers, or 4) the next 3 spins produce 3 more unique numbers (no repeaters), so we end up with 9 unique numbers. Notice how in scenarios 2, 3, and 4, at least 1 new unique number has appeared, which would be favorable to us since we are looking to bet on numbers that have not come out yet in a particular sequence. So to determine the probability of a new unique number appearing in the next 3 spins when 6 unique numbers have come out in a 7 consecutive spins, we simply get the proportional probability of all possible favorable scenarios where at least 1 new unique number is spun (in other words, 7, 8, or 9 unique number appearing in this case) over the probability of all possible scenarios (in other words, the unfavorable scenario of 6 unique numbers appearing plus the favorable scenarios of 7, 8, or 9 unique numbers appearing): (6% + 24% + 42%) / (1% + 6% + 24% + 42%) = 72% / 73% = 98.6%. So if 6 unique numbers come out in 7 consecutive spins, then the probability of at least 1 new unique number coming out in the next 3 spins to complete the 10-spin sequence is 98.6%. Again, don't just take my word for it, try it yourself in the interactive example below. See how often you would win if you bet whenever exactly 6 unique numbers come out in the first 7 consecutive spins (thus triggering a BET signal). Remember, you would be betting on the 31 numbers that have not come out by the 7th spin, so if any new unique number appeared in the next 3 spins (e.g. by the 10th spin), you would automatically win:

Likewise, in the original example, if 7 unique numbers came out in 7 spins, you should not account for the 1% probability of only 6 unique numbers coming out since it is impossible for 6 unique numbers to come out if 7 have already come out. So again, you would have to calculate the actual probability as the proportional probability of all possible favorable scenarios where at least 1 new unique number is spun (that is, 8, 9, or 10 unique numbers appearing in this case) over the probabilities of all possible scenarios (7, 8, 9, or 10 unique numbers appearing): (24% + 42% + 27%) / (6% + 24% + 42% + 27%) = 93% / 99% = 93.94%. This represents the actual probability of a new unique number appearing in the next 3 spins if 7 different numbers have come out in the last 7 spins. The only problem is that you do not know at what point in the next 3 spins you will win, so you need to create a progression to ensure you profit if a new unique number comes out in any of the next 3 spins. You can therefore use a 3-step progression to bet on the remaining 30 numbers that haven't occurred in the last 7 spins. The 3-step progression you would require after the 7th spin of a 10-spin sequence with 7 unique numbers already spun and betting on all the 30 unique numbers that have not yet appeared is as follows (assuming you would be content with at least a $1 profit):

Progression table for a 10-spin sequence with 7 unique numbers after 7 spins.
Betting on 30 numbers.

The catch, however, is that with such a low spin sequence (e.g. 10 spins), you would need a restrictively large bankroll and table limit to ensure a successful outcome. To complete such a progression, you would need a table limit of $36 per number bet and a $1,290 bankroll. Most Casino's have a significantly lower table limit and most players have a significantly lower bankroll. Even then, who would risk $1,290 to win $6 even with a 93.94% chance of success? Your Expected Return (in dollar terms) would be (.9394*$6) - (.0606*$1290) = -$72.54. So even if you could afford the bankroll and were at a Casino that allowed such a high table limit, your Expected Return is still negative so you would never make that bet.

This is where the Advanced Andruchi roulette system comes into play. It considers 37 consecutive spin sequences and their respective unique number probabilities based on 10 million simulations for maximum accuracy as shown below:

Probability Distribution of Unique Numbers in 37 Consecutive Spins.
Based on 10 million simulations.

The 37 consecutive spin table is a lot more interesting than the 10-spin example (find out how I calculated the probabilities in the table above). Notice how in those 10 million simulations, there was never less than 14 or more than 33 unique numbers. In other words, in 37 consecutive spins, all 37 numbers will never appear (hence why I said on the previous page that you would die trying to see all 37 roulette numbers come out in 37 consecutive spins). Not only that, but in 37 spins, 23 and 24 unique numbers are most likely to appear (each about once every 5 sequences). Furthermore, with this information, I can give you one simple winning system:

The problem with that simple System is that you would have to wait a very long time for that event to happen as it is incredibly rare for 33 different numbers to come out in under 37 consecutive spins. That is where my Andruchi Roulette System comes in as it takes into account the shifting proportional probabilities mid-sequence which exploit the table of probabilities above and leads to several favorable scenarios.

Unlike with the 10-spin example, another advantage of a 37-spin sequence is that bets are normally triggered towards the end of the sequence where, on average, one would only have to bet on approximately half the table (e.g. 17 numbers instead of 30 like in the 10-spin example), reducing the bankroll required and extending the possibility of a successful progression. Even then, it only signals a bet when the Expected Return is positive and the Probability of Success is above 90% and then automatically calculates the required progression to help ensure success. Below is a typical progression table for a 37-spin sequence where 20 unique numbers have come out in 34 consecutive spins (e.g. 3 spins left to complete the 37-spin sequence; betting on the 17 unique numbers that have not yet appeared):

Progression table for a 37-spin sequence with 20 unique numbers after 34 spins.
Betting on 17 numbers.

Compared to the progression table of the 10 consecutive spin example earlier, this progression is a lot more accessible as it only requires a $68 bankroll and a maximum of $2 per straight number bet. The Probability of Success with this example is the proportional probability of the favorable scenarios with 21, 22, or 23 unique numbers divided by the proportional probability of all scenarios with 20, 21, 22, or 23 unique numbers (confer above): (8% + 15% + 20%) / (4% + 8% + 15% + 20%) = 92.29% (this is calculated instantly and automatically by my Advanced Andruchi Roulette System every time you enter a new spin). Since we do not know at what point in the progression we will be successful and each step of the progression offers a different profit, we must again average the Profit column, giving us an Average Profit of $8.33. Using this Average Profit, we can calculate the Expected Return: (.9229 * $8.33) - (.0771 * $68) = $2.45. Unlike with the 10 consecutive spin example, we now actually have a Positive Expected Return in this scenario. Considering that 1) we have a positive Expected Return, 2) the units required in the progression are well below the table limit, and 3) the bankroll is very accessible, we would proceed to bet. Of course, the Advanced Andruchi roulette system calculates everything instantly and automatically - including the proportional probabilities, progression table, and Expected Returns - from the spins you enter and signals a bet when appropriate, telling you exactly on what numbers to bet (which are simply the numbers that have not appeared by that point in the 37 consecutive spin sequence). The fact that it only signals a Bet when the Expected Return is positive is very important because that is what ensures it wins consistently in the long run. So all you have to do is enter the spins as they are generated, wait for a Bet signal, and place the bets on the specified numbers. It is as simple as it is effective.

Below is a screenshot of the Advanced Andruchi roulette system in action. The System is very simply to use and extremely accurate and effective. The only catch is that not every 37-spin sequence will trigger a Bet, although most will. However, using the program's Smart Clear feature will allow you to clear only the initial spins necessary to return to a positive scenario, taking advantage of the most recent spins already recorded, thereby dramatically speeding up the time it takes for a Bet to be signaled. In other words, the Smart Clear button allows you to use the end of a previous sequence as the beginning of a new sequence, instead of starting a new 37-spin sequence from scratch. Since the Probabilities of Success given are not some random number I invented, but a mathematically-derived probability based on actual outcomes in 10-million simulations of 37-spin sequences, the player knows precisely what chance they have of being successful on any given bet signal. Since they will rarely encounter a 100% Probability of Success, you need to allow room for losses. However, considering the fact that you are always placing bets when a positive Expected Return is given and the Probability of Success is 90% or greater, then the winners will more than compensate for the losers and you will be winning in over 9 out of every 10 Bet signals, resulting in consistent long-term profitability, and a winning system by definition. Now let me show you a real-world Example of my System in Action.